Question

A square and a quadrilateral triangle have a side in common. If side of triangle is $\frac{3}{4}cm$ long. Find the perimeter of figure formed.

Answer 1

$\begin{array}{c}AB=\frac{3}{4}cm\\ perimeterofgivenfigure\\ AB+BD+DE+EC+AC\\ =\frac{3}{4}cm+\frac{3}{4}cm+\frac{3}{4}cm+\frac{3}{4}cm+\frac{3}{4}cm\\ =5\times \frac{3}{4}=\frac{15}{4}=3\frac{3}{4}cm\end{array}$