A square coil of side 10 cm consists of 20 turns and carries a current of 12 A- The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30-o with the direction of a uniform horizontal magnetic field of magnitude 0-80 T- What is the magnitude of torque experienced by the coil-

Question

Toppr Admin · Accepted Answer

Magnitude of torque experienced by coil in the magnetic field is given by-x3C4-nBIAsin-x3B8-0-96-xA0-Nmwhere A-l-xD7-l

Magnitude of torque experienced by coil in the magnetic field is given by,τ=nBIAsinθ=0.96 Nmwhere A=l×l

Magnitude of torque experienced by coil in the magnetic field is given by,
$τ = n B I A s i n θ = 0.96 N m$
where $A = l \times l$