A standing wave having 3 nodes and 2 antinodes is formed between two atoms having a distance 1.21˚A between them. The wavelength of the standing wave is
3.63˚A
1.21˚A
4.84˚A
5.86˚A
A
4.84˚A
B
3.63˚A
C
1.21˚A
D
5.86˚A
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Solution
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The correct option is A1.21˚A The given situation can be shown as Given the distance between the two atoms =1.21˚A so, the wavelength of the standing wave is λ2+λ2=λ=1.21˚A
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