A stationary thorium nucleus -A-220- Z-90- emits an alpha particle with kinetic energy E-alpha- What is the kinetic energy of the recoiling nucleus-dfrac -E-alpha-108-dfrac -E-alpha-110-dfrac -E-alpha-55-dfrac -E-alpha-54-

Question

Toppr Admin · Accepted Answer

220Z90-x2192-x3B1-XmX-220-x2212-m-x3B1-216-xA0-E-p22mp-x221A-2mE

A stationary thorium nucleus $(A = 220, Z = 90)$ emits an alpha particle with kinetic energy $E_{α}$ . What is the kinetic energy of the recoiling nucleus?
$\frac{E_{α}}{108}$
$\frac{E_{α}}{110}$
$\frac{E_{α}}{55}$
$\frac{E_{α}}{54}$

$^{220} Z_{90} \to α + X$
$m_{X} = 220 - m_{α} = 216$

$E = \frac{p^{2}}{2 m}$
$p = \sqrt{2 m E}$

A stationary thorium nucleus (A=220,Z=90) emits an alpha particle with kinetic energy Eα. What is the kinetic energy of the recoiling nucleus?Eα108Eα110Eα55Eα54

220Z90→α+XmX=220−mα=216 E=p22mp=√2mE

A stationary thorium nucleus $(A = 220, Z = 90)$ emits an alpha particle with kinetic energy $E_{α}$ . What is the kinetic energy of the recoiling nucleus?
$\frac{E_{α}}{108}$
$\frac{E_{α}}{110}$
$\frac{E_{α}}{55}$
$\frac{E_{α}}{54}$

$^{220} Z_{90} \to α + X$
$m_{X} = 220 - m_{α} = 216$

$E = \frac{p^{2}}{2 m}$
$p = \sqrt{2 m E}$