A steel is 1 m long and 1mm2 in area of cross-section .If it takes 200 N to stretch this wire by 1 mm , how much force will be required to stretch a wire of the same material as well as diameter from its normal length of 10 m to a length of 1002 cm ?
2000 N
400 N
1000 N
200 N
A
1000 N
B
400 N
C
2000 N
D
200 N
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Solution
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The correct option is C 400 N Given, A steel wire Length (L)=1m Area (A)=1mm2=1×10−6m2 - it takes 200N and ΔL=1mm=10−3m From above data,
Young modulus = stress strain =FLAΔL=200×110−6×10−3y=2×1011N/m2
when L=10mΔL=2cm=0.02mF=? we know y=FLAΔLF=yAΔLL=2×1011×10−6×0.0210F=400N
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