A steel scale is correct at 0oC, the length of a brass tube measured by it at 40oC is 5m. The correct length of the tube at 0oC is (Coefficients of linear expansion of steel and brass are 11×10−6/oC and 19×10−6/oC respectively).
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Actual length of brass tube, lb=?
For Length of scale at 00=ls,l′s=ls(1+αsΔT)
Actual length of tube at 400
Actual length of tube at 00c=lb
Let the length of tube and scale at 0oC be l. Then,
Change in measured tube length
Δl=Thermal expansion of brass− Thermal expansion of steel
So, new length measured by scale=l+Δl
Option C is correct.
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