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Question

A stellite of mass m is orbiting the earth (of radius R) at a height h from its surface. The total energy of the stellite in terms of g0, value of acceleration due to gravity at the earth's surface, is
  1. 2mg0R2R+h
  2. mg0R22(R+h)
  3. mg0R22(R+h)
  4. 2mg0R2R+h

A
mg0R22(R+h)
B
2mg0R2R+h
C
mg0R22(R+h)
D
2mg0R2R+h
Solution
Verified by Toppr

Total energy of the satellite T=GMm2r where r=R+h
T=GMm2(R+h)
Acceleration due to gravity at earth's surface go=GMR2 GM=goR2
T=mgoR22(R+h)

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