A stone is dropped from a height of 9 meters above the ground- If the height can be modeled by the equation h-t- a -t-2- where t is time in seconds- h is height in meters- and a is the initial height- how many seconds does it take the stone to hit the ground-

Question

Toppr Admin · Accepted Answer

Height of the ball is under function- h-t-a-x2212-t2at time- t-0-h-9-x2234-9-a-x2212-0a-9We have to find time at which h-00-9-x2212-t2t2-9t-3 -correct Answer-

A stone is dropped from a height of 9 meters above the ground. If the height function can be modeled by the equation $h (t) = a - t^{2}$ , where t is time in seconds, h is height in meters, and a is the initial height, how many seconds does it take for the stone to hit the ground?

Height of the ball is under function, $h (t) = a - t^{2}$
at time, $t = 0, h = 9$
$∴ 9 = a - 0$
$a = 9$
We have to find time at which $h = 0$
$0 = 9 - t^{2}$
$t^{2} = 9$
$t = 3$ (correct Answer)

A stone is dropped from a height of 9 meters above the ground. If the height function can be modeled by the equation h(t)=a−t2, where t is time in seconds, h is height in meters, and a is the initial height, how many seconds does it take for the stone to hit the ground?

Height of the ball is under function, h(t)=a−t2at time, t=0,h=9∴9=a−0a=9We have to find time at which h=00=9−t2t2=9t=3 (correct Answer)

A stone is dropped from a height of 9 meters above the ground. If the height function can be modeled by the equation $h (t) = a - t^{2}$ , where t is time in seconds, h is height in meters, and a is the initial height, how many seconds does it take for the stone to hit the ground?

Height of the ball is under function, $h (t) = a - t^{2}$
at time, $t = 0, h = 9$
$∴ 9 = a - 0$
$a = 9$
We have to find time at which $h = 0$
$0 = 9 - t^{2}$
$t^{2} = 9$
$t = 3$ (correct Answer)