A stone of mass 2 kg is dropped from a height 40 meter. Calculate the speed when it hits the ground.Assume a constant air resistance force 20 N act on it.
A
8 m/s
B
10 m/s
C
12 m/s
D
16 m/s
E
0 m/s
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Solution
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Given : h=40 m m=2kgu=0m/s
Force due to air resistance f=20N
Acceleration of the stone a=g−fm=10−202=0m/s2
Using v2−u2=2aS
∴v2−0=2(0)×40⟹v=0m/s
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