A stop-cock connecting two bulbs of 3L and 5L, containing an ideal gas at 10 atm and 12 atm respectively, is opened. What is the final pressure, if the two bulbs are opened at the same temperature?
11.3 atm
22.6 atm
9 atm
12 atm
A
9 atm
B
11.3 atm
C
22.6 atm
D
12 atm
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Solution
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Bulb 1, P1V1=n1RT Bulb 2, P2V2=n2RT
On mixing, P1V1+P2V2=(n1+n2)RT.......(i)
After opening, let the pressure be P.
P(V1+V2)=(n1+n2)RT.......(ii)
From (i) and (ii), P1V1+P2V2=P(V1+V2)
⟹10×3+12×5=P(8)
P=908=11.3atm
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