A string of length- L- is fixed one end and carries a mass- M the other end- The string makes 2-pi revolutions per second around the vertical axis through the fixed end as shown in the figure- then tension in the string isML2 ML4 ML16 ML

Question

Toppr Admin · Accepted Answer

Given - -xA0- -xA0- -xA0- -xA0-w-2-x3C0- rev- per sec -xA0- -xA0- -xA0- -xA0-x27F9-w-2-x3C0-x3BD-4From figure -xA0- -xA0- -xA0- R-Lsin-x3B8-x2234- -xA0- -xA0-Tsin-x3B8-MRw2-x27F9- -xA0- -xA0- -xA0- T-MLw2-ML-4-2-16ML -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-xA0-

A string of length, $L$ , is fixed at one end and carries a mass, $M$ at the other end. The string makes $2 / π$ revolutions per second around the vertical axis through the fixed end as shown in the figure, then tension in the string is

$M L$
$2 M L$
$4 M L$
$16 M L$

Given : $w = \frac{2}{π}$ rev. per sec $⟹ w = 2 π ν = 4$
From figure $R = L s i n θ$
$∴$ $T s i n θ = M R w^{2}$
$⟹$ $T = M L w^{2} = M L (4)^{2} = 16 M L$

A string of length, L, is fixed at one end and carries a mass, M at the other end. The string makes 2/π revolutions per second around the vertical axis through the fixed end as shown in the figure, then tension in the string isML2ML4ML16ML

Given : w=2π rev. per sec ⟹w=2πν=4From figure R=Lsinθ∴ Tsinθ=MRw2⟹ T=MLw2=ML(4)2=16ML

A string of length, $L$ , is fixed at one end and carries a mass, $M$ at the other end. The string makes $2 / π$ revolutions per second around the vertical axis through the fixed end as shown in the figure, then tension in the string is

$M L$
$2 M L$
$4 M L$
$16 M L$

Given : $w = \frac{2}{π}$ rev. per sec $⟹ w = 2 π ν = 4$
From figure $R = L s i n θ$
$∴$ $T s i n θ = M R w^{2}$
$⟹$ $T = M L w^{2} = M L (4)^{2} = 16 M L$