A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by
√2Mg
√2mg
g[√(M+m)2+M2]
g[√(M+m)2+m2]
A
√2mg
B
g[√(M+m)2+m2]
C
g[√(M+m)2+M2]
D
√2Mg
Open in App
Solution
The correct option is Dg[√(M+m)2+M2] F.B.D of pulley
F1=(m+M)g The resultant force on pulley is F=√F21+T2 F=[√(m+M)2+M2]g
Was this answer helpful?
5
Similar Questions
Q1
A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by
View Solution
Q2
A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by
View Solution
Q3
A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is
View Solution
Q4
A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by (Take acceleration due to gravity=g)
View Solution
Q5
A string of negligible mass going over a clamped ideal pulley supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by