A student completed a genetics exercise by preparing this Punnett square. [Note: 'T' represents a dominant allele and 't' represents a recessive allele.]
What were the likely genotypes of the parents ?

Parent 1 was heterozygous, parent 2 was homozygous.
Both parents were homozygous.
Both parents were heterozygous.
Parent 1 was homozygous, parent 2 was heterozygous.

Question

A student completed a genetics exercise by preparing this Punnett square. [Note: 'T' represents a dominant allele and 't' represents a recessive allele.]
What were the likely genotypes of the parents ?

Parent 1 was heterozygous, parent 2 was homozygous.
Both parents were homozygous.
Both parents were heterozygous.
Parent 1 was homozygous, parent 2 was heterozygous.

Toppr Admin · Accepted Answer

The -x201C-3 dominant- 1 recessive-x201D- phenotypic ratio or -x201C-1 homozygous dominant -2 heterozygous dominant- 1 homozygous recessive-x201D- genotypic ratio is obtained by self pollination of F1 monohybrid- Thus- both parents are heterozygous tall -Tt- The presence of one homozygous parent would given the monohybrid test cross ratio of 1-1- Homozygous varieties produce uniform F1 generation of dominant or recessive individuals depending upon the genotype of homozygous parent- Thus- the correct answer is option C-