A student secures 90- 60- and 54- mark in test papers with 100- 150 and 200 respectively as maximum marks- The percentage of his aggregate is-64-68-70-none of these

Question

Toppr Admin · Accepted Answer

Let us consider the total scored -90-0f100-60-of150-54-of200-90100-xD7-100-60100-xD7-150-54100-xD7-200-288Total maximum marks -100-150-200-450Aggregate percentage -288450-xD7-100-64-

A student secures $90 %, 60 %$ , and $54 %$ mark in test papers with $100, 150$ and $200$ respectively as maximum marks. The percentage of his aggregate is:
$64 %$
$68 %$
$70 %$
$n o n e o f t h e s e$

Let us consider the total scored $= (90 % 0 f 100 + 60 % o f 150 + 54 % o f 200)$
$(\frac{90}{100} \times 100 + \frac{60}{100} \times 150 + \frac{54}{100} \times 200)$
$= 288$
Total maximum marks $= (100 + 150 + 200) = 450$
Aggregate percentage $= (\frac{288}{450} \times 100) %$
$= 64 %$

A student secures 90%,60%, and 54% mark in test papers with 100,150 and 200 respectively as maximum marks. The percentage of his aggregate is:64%68%70%none of these

Let us consider the total scored =(90%0f100+60%of150+54%of200)(90100×100+60100×150+54100×200)=288Total maximum marks =(100+150+200)=450Aggregate percentage =(288450×100)%=64%

A student secures $90 %, 60 %$ , and $54 %$ mark in test papers with $100, 150$ and $200$ respectively as maximum marks. The percentage of his aggregate is:
$64 %$
$68 %$
$70 %$
$n o n e o f t h e s e$

Let us consider the total scored $= (90 % 0 f 100 + 60 % o f 150 + 54 % o f 200)$
$(\frac{90}{100} \times 100 + \frac{60}{100} \times 150 + \frac{54}{100} \times 200)$
$= 288$
Total maximum marks $= (100 + 150 + 200) = 450$
Aggregate percentage $= (\frac{288}{450} \times 100) %$
$= 64 %$