A substitution reaction of methane is-CH-4- - Cl-2- rightarrow CCl-4 - HClCH-4- - Cl-2- rightarrow CHCl-3 - HClCH-4- - Cl-2- rightarrow CH-3-Cl - HClCH-4- - Cl-2- rightarrow CH-2-Cl-2 - HCl

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Question

A substitution reaction of methane is:
$C H_{4} + C l_{2} \to C C l_{4} + H C l$
$C H_{4} + C l_{2} \to C H C l_{3} + H C l$
$C H_{4} + C l_{2} \to C H_{3} C l + H C l$
$C H_{4} + C l_{2} \to C H_{2} C l_{2} + H C l$

C H_{4} + C l_{2} \to C H C l_{3} + H C l

C H_{4} + C l_{2} \to C H_{2} C l_{2} + H C l

C H_{4} + C l_{2} \to C C l_{4} + H C l

C H_{4} + C l_{2} \to C H_{3} C l + H C l

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Solution

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When a mixture of methane and chlorine is exposed to ultraviolet light - typically sunlight - a substitution reaction occurs and the organic product is chloromethane. The reaction can be written as: $C H_{4} + C l_{2} \to C H_{3} C l + H C l$

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Similar Questions

In which of the following reactions, chlorine acts as an oxidising agent?
(i)

C H_{3} C H_{2} O H + {C l}_{2} ⟶ C H_{3} C H O + H C l

(ii)

C H_{3} C H O + {C l}_{2} ⟶ C {C l}_{3} C H O + H C l

(iii)

C H_{4} + {C l}_{2} ⟶ C H_{3} C l + H C l

View Solution

Consider two alternative mechanism for the chlorination of methane. Which step is crucial in deciding which mechanism is not likely to be observed?
Mechanism I Mechanism II

A ${C l}_{2} ⟶ {2 C l}^{∙}$	A ${C l}_{2} ⟶ {2 C l}^{∙}$
B ${C l}^{∙} + {C H}_{4} ⟶ H C l +^{∙} {C H}_{3}$	D ${C l}^{∙} + {C H}_{4} ⟶ {C H}_{3} C l + H^{∙}$
C $∙ C H_{3} + {C l}_{2} ⟶ {C H}_{3} C l + {C l}^{∙}$	E $H^{∙} + {C l}_{2} ⟶ H C l + {C l}^{∙}$

View Solution

C H_{4} + C l_{2} h v - \to C H_{3} C l + H C l

To obtain high yields of

C H_{3} C l,

the ratio of

C H_{4}

C l_{2}

must be:

View Solution

Consider two alternative mechanisms for the chlorination of methane, Which step is crucial in deciding which mechanism is not likely to be observed?
Mechanism I:

A . C l_{2} \to 2 C l^{*}

B . C l^{*} + C H_{4} \to H C l +^{*} C H_{3}

C . ˙ C H_{3} + C l_{2} \to C H_{3} C l + C l^{*}

Mechanism II:

D . C l_{2} \to 2 C l^{*}

E . C l^{*} + C H_{4} \to C H_{3} C l + H^{*}

F . H^{*} + C l_{2} \to H C l + C l^{*}

View Solution

In which of the following reactions chlorine acts an oxidising agent.

C H_{3} C H_{2} O H + C l_{2} \to C H_{3} C H O + H C l

ii)

C H_{3} C H O + C l_{2} \to C C l_{3} C H O + H C l

iii)

C H_{4} + C l h v - \to C H_{3} C l + H C l

The correct answer is :

View Solution

A substitution reaction of methane is:CH4+Cl2→CCl4+HClCH4+Cl2→CHCl3+HClCH4+Cl2→CH3Cl+HClCH4+Cl2→CH2Cl2+HCl

When a mixture of methane and chlorine is exposed to ultraviolet light - typically sunlight - a substitution reaction occurs and the organic product is chloromethane. The reaction can be written as: CH4+Cl2→CH3Cl+HCl

A substitution reaction of methane is:
$C H_{4} + C l_{2} \to C C l_{4} + H C l$
$C H_{4} + C l_{2} \to C H C l_{3} + H C l$
$C H_{4} + C l_{2} \to C H_{3} C l + H C l$
$C H_{4} + C l_{2} \to C H_{2} C l_{2} + H C l$

When a mixture of methane and chlorine is exposed to ultraviolet light - typically sunlight - a substitution reaction occurs and the organic product is chloromethane. The reaction can be written as: $C H_{4} + C l_{2} \to C H_{3} C l + H C l$