A system has two charges q-A - 2-5times 10-7- C and q-B - -2-5times 10-7-C located points A- -0- 0- 15 cm- and B- -0-0- -15 cm- respectively- What are the total charge and electric dipole moment of the system-

Question

Toppr Admin · Accepted Answer

According to the figure given below both the charges can be located in a coordinate frame of reference.

At A, amount of charge, $q_{A} = 2.5 \times 10^{- 7} C$ (Given)
At B, amount of charge, $q_{B} = - 2.5 \times 10^{- 7} C$ (Given)
Total charge of the system,
$a = q_{A} + q_{B} = 2.5 \times 10^{- 7} C - 2.5 \times 10^{- 7} C = 0$
Distance between two charges at points A and B,
$d = 15 + 15 = 30 c m = 0.3 m$
Electric dipole moment of the system is given by,
$p = q_{A} \times d = q_{B} \times d = 2.5 \times 10^{- 7} \times 0.3 = 7.5 \times 10^{- 8} C m$ along positive z-axis
Therefore, the electric dipole moment of the system is $7.5 \times 10^{- 8} C m$ along positive z−axis.

A system has two charges qA=2.5×10−7C and qB=−2.5×10−7C located at points A:(0,0,15cm) and B:(0,0,+15cm), respectively. What are the total charge and electric dipole moment of the system?

A system has two charges $q_{A} = 2.5 \times 10^{- 7} C$ and $q_{B} = - 2.5 \times 10^{- 7} C$ located at points $A : (0, 0, 15 c m)$ and $B : (0, 0, + 15 c m)$ , respectively. What are the total charge and electric dipole moment of the system?