A table is in the shape of a trapezium. Its parallel sides are $$8\,m$$, and $$16\,m$$ respectively. Area of table is $$108\,sq.\,m$$. Find the width of the table i.e. Distance between the parallel sides.
Let distance between the parallel sides be h.
Area of trapezium$$=\dfrac{1}{2} \times (sum\,of \,the\,parallel\,sides) \times$$ distance between the parallel sides
$$\Rightarrow 108=\dfrac{1}{2} \times (8+16) \times h$$
$$\therefore x=\dfrac{108 \times 2}{24} \Rightarrow x=9\,m$$
Hence, distance between the parallel sides be $$9 \,m$$.