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Question

A table is in the shape of a trapezium. Its parallel sides are $$8\,m$$, and $$16\,m$$ respectively. Area of table is $$108\,sq.\,m$$. Find the width of the table i.e. Distance between the parallel sides.

Solution
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Let distance between the parallel sides be h.

Area of trapezium$$=\dfrac{1}{2} \times (sum\,of \,the\,parallel\,sides) \times$$ distance between the parallel sides

$$\Rightarrow 108=\dfrac{1}{2} \times (8+16) \times h$$

$$\therefore x=\dfrac{108 \times 2}{24} \Rightarrow x=9\,m$$

Hence, distance between the parallel sides be $$9 \,m$$.

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