A tall plant -TT- is crossed with a dwarf plant -tt- All -F-1- plants showed tall phenotype- Which of the following correctly defines a test cross-TT-F-1-times Tt-P-Tt-F-1-times Tt-P-tt-F-1-times Tt-P-Tt-F-1-times tt-P-

Question

Toppr Admin · Accepted Answer

A test cross is defined as the cross between the unknown genotype of the F1 generation with the double recessive parent -phenotypically-xA0-So- the correct test cross will be- Tt -F1- x tt -recessive parent-So- the correct answer is -apos-Option D- Tt -F1- x tt -P-apos-

A tall plant (TT) is crossed with a dwarf plant (tt). All $F_{1}$ plants showed tall phenotype. Which of the following correctly defines a test cross?
$T T (F_{1}) \times T t (P)$
$T t (F_{1}) \times T t (P)$
$t t (F_{1}) \times T t (P)$
$T t (F_{1}) \times t t (P)$

A test cross is defined as the cross between the unknown genotype of the F1 generation with the double recessive parent (phenotypically).
So, the correct test cross will be: Tt (F1) x tt (recessive parent)
So, the correct answer is 'Option D- Tt (F1) x tt (P)'.

A tall plant (TT) is crossed with a dwarf plant (tt). All F1 plants showed tall phenotype. Which of the following correctly defines a test cross?TT(F1)×Tt(P)Tt(F1)×Tt(P)tt(F1)×Tt(P)Tt(F1)×tt(P)

A test cross is defined as the cross between the unknown genotype of the F1 generation with the double recessive parent (phenotypically). So, the correct test cross will be: Tt (F1) x tt (recessive parent)So, the correct answer is 'Option D- Tt (F1) x tt (P)'.

A tall plant (TT) is crossed with a dwarf plant (tt). All $F_{1}$ plants showed tall phenotype. Which of the following correctly defines a test cross?
$T T (F_{1}) \times T t (P)$
$T t (F_{1}) \times T t (P)$
$t t (F_{1}) \times T t (P)$
$T t (F_{1}) \times t t (P)$

A test cross is defined as the cross between the unknown genotype of the F1 generation with the double recessive parent (phenotypically).
So, the correct test cross will be: Tt (F1) x tt (recessive parent)
So, the correct answer is 'Option D- Tt (F1) x tt (P)'.