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Question

A tank is filled with water up to height $H$ . Water is allowed to come out of a hole P in one of the walls at a depth $D$ below the surface of water. The horizontal distance $x$ in terms of $H$ and $D$ will be expressed as :

$x = 2 \sqrt{D (H - D)}$
$x = \sqrt{\frac{D (H - D)}{2}}$
$x = 4 \sqrt{D (H - D)}$
$x = \sqrt{D (H - D)}$

A

x = \sqrt{\frac{D (H - D)}{2}}

B

x = 2 \sqrt{D (H - D)}

C

x = \sqrt{D (H - D)}

D

x = 4 \sqrt{D (H - D)}

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Solution

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Answer is C.

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