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Question

A tent is in the form of a right circular cylinder, surmounted by a cone. The diameter of the cylinder is 24 m. The height of the cylindrical portion is 11 m, while the vertex of the cone is 16 m above the ground.
The curved surface area of the cylindrical portion is

  1. (246π)m2
  2. (426π)m2
  3. (462π)m2
  4. (264π)m2

A
(264π)m2
B
(462π)m2
C
(246π)m2
D
(426π)m2
Solution
Verified by Toppr

Given, diameter =24 m
Therefore, radius =d2=242=12 m
and height given is 11 m
Therefore, curved surface area of the cylinder =2(π)rh
=2×(π)×12×11
=264(π)

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