0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# A test $$1.6 \times 10^{-19} Cb$$ is moving with velocity $$\overrightarrow v = ( 2 \hat i +3 \hat j)$$ m/sec is magnetic field $$\overrightarrow B = ( 2 \hat i + 3 \hat j ) wb /m^2$$ .the magnetic force on the test charge:-

A
$$6 \hat k T$$
B
$$( 4 \hat i + 6 \hat j ) T$$
C
$$( 4 \hat i + 6 \hat j ) \times 10^{-19} T$$
D
zero
Solution
Verified by Toppr

#### Correct option is D. zeroGivenCharge=$$1.6*10^{-19}$$v=(2i+3j) m/sB=(2i+3j) wb/mSolutionForce=q(vxB)Cross product of v and B is 0Therefore F is 0The correct option is D

13
Similar Questions
Q1
A test $$1.6 \times 10^{-19} Cb$$ is moving with velocity $$\overrightarrow v = ( 2 \hat i +3 \hat j)$$ m/sec is magnetic field $$\overrightarrow B = ( 2 \hat i + 3 \hat j ) wb /m^2$$ .the magnetic force on the test charge:-
View Solution
Q2
The magnetic force acting on a charged particle of charge2μC in a magnetic field of 2T acting in y-direction, when the particle velocity is (2^i+3^j) × 106 ms1 is :
View Solution
Q3
A charge q=4μC has an instantaneous velocity v=(2^i3^j+^k)×106m/s in a uniform magnetic field B=(2^i+5^j3^k)×102T.What is the force on the charge?
View Solution
Q4
If an electron moves with a velocity, $$\vec{v} = (2\hat{i} - 3\hat{j} + \hat{k}) \,m/s$$ in a magnetic field, $$\vec{B} = (2\hat{i} + \hat{j} - \hat{k})T.$$ then, calculate the Lorentz force.
View Solution
Q5
A particle of mass 1 mg and having charge 1 μC is moving in a magnetic field, B=(2^i+3^j+^k) T with velocity v=(2^i+^j^k) km/s. Find the magnitude of acceleration.
View Solution