A test tube containing some water is surrounded by melting ice (pure). Then, the water in the test tube will

Question

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Answer 1

A test tube containing water which is surrounded by melting ice cannot freeze into ice because first of all after sometime both water and melting ice will come at $0^{o} C$ . And while water is converted into ice, it releases heat and there is nothing which can absorb latent heat of fusion which is released by freezing water.

Answer 2

A test tube containing water which is surrounded by melting ice cannot freeze into ice because first of all after sometime both water and melting ice will come at

0^{o} C

. And while water is converted into ice, it releases heat and there is nothing which can absorb latent heat of fusion which is released by freezing water.

A test tube containing some water is surrounded by melting ice (pure). Then, the water in the test tube will

not freeze into ice

freeze into ice

boil ultimately

become steam ultimately

The triple point of water is

Ice -Water mass ratio is maintained as $1 : 1$ in a given system containing water in equilibrium with ice at constant pressure. If $C_{P}$ (ice) = $C_{P}$ (water) = 4.18 J $m o l^{- 1} K^{- 1}$ molar heat capacity of such a system is

Ice melts when energy in the form of ----- is supplied.

A piece of ice floating in a glass of water melts, but the level of water in glass does not change. Give reason.

If melting point of ice is $0^{o} C$ , then solidification point of water is also $0^{o} C .$

If the boiling point of water is $10 0^{o} C$ , then liquefaction point of steam is also $10 0^{o} C$ .

Revise with Concepts

Advanced Knowledge of Change of State

A test tube containing some water is surrounded by melting ice (pure). Then, the water in the test tube will

not freeze into ice

freeze into ice

boil ultimately

become steam ultimately

The triple point of water is

Ice -Water mass ratio is maintained as 1:1 in a given system containing water in equilibrium with ice at constant pressure. If CP​ (ice) = CP​ (water) = 4.18 J mol−1K−1 molar heat capacity of such a system is

Ice melts when energy in the form of ----- is supplied.

A piece of ice floating in a glass of water melts, but the level of water in glass does not change. Give reason.

If melting point of ice is 0oC, then solidification point of water is also 0oC.

If the boiling point of water is 100oC, then liquefaction point of steam is also 100oC.

Revise with Concepts

Advanced Knowledge of Change of State

Ice -Water mass ratio is maintained as $1 : 1$ in a given system containing water in equilibrium with ice at constant pressure. If $C_{P}$ (ice) = $C_{P}$ (water) = 4.18 J $m o l^{- 1} K^{- 1}$ molar heat capacity of such a system is

If melting point of ice is $0^{o} C$ , then solidification point of water is also $0^{o} C .$

If the boiling point of water is $10 0^{o} C$ , then liquefaction point of steam is also $10 0^{o} C$ .