A thermally isolated vessel contains 100g of water at 0oC When air above the wall pumped out, some of the water freezes and some evaporates at 0oC itself. Calculate the number of the ice formed if no water is left in the vessel. Latent heat of vaporization of water 0oC=×106Jkg−1 and latent heat of fusion of ice =3.36×105Jkg−1
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Solution
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The total amount is given as,
x+y=100 (1)
Heat lost=
Heat Gained
y×3.36×105=x×2.1×106
yx=213.36 (2)
From equation (1) and (2), we get
y=2100002436
y=86.21g
The amount of ice formed is 86.21g.
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