Question

A thermodynamic cycle $$xyzx$$ is shown on a $$V-T$$ diagram.
The $$P-V$$ diagram that best describes this cycle is : (Diagrams are schematic and not to scale)

Answer 1

Correct option is C.
Consider the path $$xy$$, [ref. image 1]

$$V \propto T$$, $$V = KT$$

Also, $$PV = nRT$$

$$\therefore P = \dfrac{nRT}{V} = \dfrac{nRT}{KT} = \dfrac{nR}{K}$$

$$\therefore P$$ is a constant.

$$\therefore$$ path $$xy$$ corresponds to isobaric process.

Consider the path $$yz$$.

Volume is constant.

Consider the path $$zx$$

Temperature is constant. (isothermal process)

or $$PV = $$ constant and $$P = \dfrac{K'}{V}$$

The graph corresponding to path $$zx$$ will be a rectangular hyperbola. [ref. image 2]