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# A thin convergent glass lens (μg=1.5) has a power of +5.0 D. When this lens is immersed in a liquid of refractive index μ, it acts as a divergent lens of focal length 100 cm. The value of μ must be4/35/35/46/5

A
4/3
B
5/3
C
6/5
D
5/4
Solution
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#### PaP1=(μgμa−1)(μgμ1−1)=+5−100/100=+5−5(μgμ1−1)=μgμa−11.5μ1−1=−15(1.5−1)=−0.1;μ1=1.50.9=53

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