A thin convex lens made of glass of μ= 1.5 has refracting surfaces of radii of curvature 10 cm each. The left space of lens contains air and the right space is filled with water of refractive index 43. A parallel beam of light is incident on it. The position of the image is :
20cm
16cm
24cm
10cm
A
24cm
B
16cm
C
20cm
D
10cm
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Solution
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Data: μa=1,μg=1.5,μw=1.33,R1=10cm,R2=−10cm,u=−∞
For left surface,
μgv1−μau=μg−μaR1
For right surface,
μwv−μgv1=μw−μgR2
From above two,
μwv−μau=μg−μaR1+μw−μgR2
or, 1.33v=1.5−110−1.33−110
v=1.33×100.66=20cm
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