A thin prism - P - 1 - with angle - 4 - circ - and made from glass of refractive index 1-54 is combined with another prism - P - 2 - made from glass of refractive index 1-72 to produce dispersion without deviation- the angle of prism - P - 2 - is - - 5-33 - circ - - 4 - circ - - 3 - circ - - 2-6 - circ -

Question

A thin prism  - P - 1 - with angle  - 4 - circ - and made from glass of refractive index 1-54 is combined with another prism  - P - 2 - made from glass of refractive index 1-72 to produce dispersion without deviation- the angle of prism - P - 2 - is - - 5-33 - circ - - 4 - circ - - 3 - circ - - 2-6 - circ -

Toppr Admin · Accepted Answer

For dispersion without deviation-x3BC-1-x2212-1-xD7-A1-x3BC-2-x2212-1-xD7-A2-x3BC-1-1-54-A1-4-xB0-x3BC-2-1-72-1-54-x2212-1-xD7-4-1-72-x2212-1-xD7-A2-gt- A2-3-x2218-

A thin prism $P_{1}$ with angle $4^{\circ}$ and made from glass of refractive index 1.54 is combined with another prism $P_{2}$ made from glass of refractive index 1.72 to produce dispersion without deviation. the angle of prism $P_{2}$ is :
${5.33}^{\circ}$
$4^{\circ}$
$3^{\circ}$
${2.6}^{\circ}$

For dispersion without deviation,

$(μ_{1} - 1) \times A_{1} = (μ_{2} - 1) \times A_{2}$

$μ_{1} = 1.54, A_{1} = 4 °, μ_{2} = 1.72$

$(1.54 - 1) \times 4 = (1.72 - 1) \times A_{2}$

=> $A_{2} = 3^{\circ}$ .

A thin prism P1 with angle 4∘ and made from glass of refractive index 1.54 is combined with another prism P2 made from glass of refractive index 1.72 to produce dispersion without deviation. the angle of prism P2 is :5.33∘4∘3∘2.6∘

For dispersion without deviation,(μ1−1)×A1=(μ2−1)×A2μ1=1.54,A1=4°,μ2=1.72(1.54−1)×4=(1.72−1)×A2=> A2=3∘.

A thin prism $P_{1}$ with angle $4^{\circ}$ and made from glass of refractive index 1.54 is combined with another prism $P_{2}$ made from glass of refractive index 1.72 to produce dispersion without deviation. the angle of prism $P_{2}$ is :
${5.33}^{\circ}$
$4^{\circ}$
$3^{\circ}$
${2.6}^{\circ}$

For dispersion without deviation,

$(μ_{1} - 1) \times A_{1} = (μ_{2} - 1) \times A_{2}$

$μ_{1} = 1.54, A_{1} = 4 °, μ_{2} = 1.72$

$(1.54 - 1) \times 4 = (1.72 - 1) \times A_{2}$

=> $A_{2} = 3^{\circ}$ .