A thin uniformly charged disc can be imagined as a

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Answer 1

A thin uniformly charged disc can be assumed to be made of continuous collection of concentric rings. Electric field at a point is then calculated due to any one such ring and then it is integrated over all the rings to find the electric field due to whole charged disc.

Answer 2

A thin uniformly charged disc can be assumed to be made of continuous collection of concentric rings. Electric field at a point is then calculated due to any one such ring and then it is integrated over all the rings to find the electric field due to whole charged disc.

A thin uniformly charged disc can be imagined as a

discrete collection of concentric rings

continuous collection of concentric rings

discrete collection of chords

continuous collection of chords

A thin uniformly charged disc can be assumed to be made of continuous collection of concentric rings. Electric field at a point is then calculated due to any one such ring and then it is integrated over all the rings to find the electric field due to whole charged disc.

A very thin disc is uniformly charged with surface charge density $σ > 0$ . Then the electric field intensity on the axis at the point from which the disc is seen at an solid angle $Ω$ is

Find the electric field on the axis of a uniformly charged disc.

A uniformly charged disc has a pin hole at its centre. The electric field at the centre of the disc is zero

Disc can be supported to be made up of many rings. also electric field at the centre of uniformly charged ring is zero

The electric field due to a uniformly charged disc at a point very distant from the surface of the disc is given by
[ $σ$ is the surface charge density on the disc]

There is a uniformly charged disc of radius $R 3$ and surface charge density $σ$ work done by electric field to brought a charge $ϱ$ From centre of disc to distance R along its axis will be :-

A thin uniformly charged disc can be imagined as a

discrete collection of concentric rings

continuous collection of concentric rings

discrete collection of chords

continuous collection of chords

A thin uniformly charged disc can be assumed to be made of continuous collection of concentric rings. Electric field at a point is then calculated due to any one such ring and then it is integrated over all the rings to find the electric field due to whole charged disc.

A very thin disc is uniformly charged with surface charge density σ>0. Then the electric field intensity on the axis at the point from which the disc is seen at an solid angle Ω is

Find the electric field on the axis of a uniformly charged disc.

A uniformly charged disc has a pin hole at its centre. The electric field at the centre of the disc is zero

Disc can be supported to be made up of many rings. also electric field at the centre of uniformly charged ring is zero

The electric field due to a uniformly charged disc at a point very distant from the surface of the disc is given by [σ is the surface charge density on the disc]

There is a uniformly charged disc of radius R3​ and surface charge density σ work done by electric field to brought a charge ϱ From centre of disc to distance R along its axis will be :-

A very thin disc is uniformly charged with surface charge density $σ > 0$ . Then the electric field intensity on the axis at the point from which the disc is seen at an solid angle $Ω$ is

The electric field due to a uniformly charged disc at a point very distant from the surface of the disc is given by
[ $σ$ is the surface charge density on the disc]

There is a uniformly charged disc of radius $R 3$ and surface charge density $σ$ work done by electric field to brought a charge $ϱ$ From centre of disc to distance R along its axis will be :-