A torque of 0-5 Nm is required to drive a screw into a wooden frame with the of a screw driver- If one of the two forces of couple produced by screw driver is 50 N- the width of the screw driver is-0-75 cm1 cm0-5 cm1-5 cm

Question

Toppr Admin · Accepted Answer

Let width be x- So the torque due to couple is 2-xD7-50-xD7-x-2-50x50x-0-5-x21D2-x-0-01m-1-xA0-cm

A torque of $0.5 N m$ is required to drive a screw into a wooden frame with the help of a screw driver. If one of the two forces of couple produced by screw driver is $50 N$ , the width of the screw driver is:
$0.75 c m$
$1 c m$
$0.5 c m$
$1.5 c m$

Let width be $x$ . So the torque due to couple is $2 \times 50 \times x / 2 = 50 x$
$50 x = 0.5 \Rightarrow x = 0.01 m = 1 c m$

A torque of 0.5Nm is required to drive a screw into a wooden frame with the help of a screw driver. If one of the two forces of couple produced by screw driver is 50N, the width of the screw driver is:0.75cm1cm0.5cm1.5cm

Let width be x. So the torque due to couple is 2×50×x/2=50x50x=0.5⇒x=0.01m=1 cm

A torque of $0.5 N m$ is required to drive a screw into a wooden frame with the help of a screw driver. If one of the two forces of couple produced by screw driver is $50 N$ , the width of the screw driver is:
$0.75 c m$
$1 c m$
$0.5 c m$
$1.5 c m$

Let width be $x$ . So the torque due to couple is $2 \times 50 \times x / 2 = 50 x$
$50 x = 0.5 \Rightarrow x = 0.01 m = 1 c m$