The distance traveled remains
xy km.
(x+10)(y−2)=xyTherefore,
xy−2x+10y−20=xy⇒−2x+10y−20=0⇒−2x+10y=20 ---------- (1)
Case 2:
Speed decreases by
10 km/h, then the time taken increases by
3 hours.
However, the distance remains,xy km.
(x−10)(y+3)=xy
Therefore, xy+3x−10y−30=xy
⇒3x−10y−30=0
⇒3x−10y=30 ---------- (2)
⇒x=50 km/h
Using this in (2), we get
150−10y=30
⇒y=12
Therefore, the distance is 50×12=600 km.