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Question

A train moves from one station to another in 2 hours time, its speed during the motion is shown in graph above. The maximum acceleration during the journey and distance covered during the time interval from 0.75 hour to 1.00 hour are
134296_a9cb10e7f40b456dbf3f6acaeea54029.png
  1. 60 kmhr2,100 km
  2. 160 kmhr2,10 km
  3. 10 kmhr2,10 km
  4. 260 kmhr2,1 km

A
160 kmhr2,10 km
B
10 kmhr2,10 km
C
260 kmhr2,1 km
D
60 kmhr2,100 km
Solution
Verified by Toppr

Maximum acceleration will occur in the region with maximum slope.
From the given curve region CD is having the maximum curve.
Thus, maximum acceleration=change in velocitychange in distance=60200.25=160
Now, total area under the curve between 0.75 to 1.00 hrs is given by
(12×0.25×40)+(20×0.25)=10km

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134296_a9cb10e7f40b456dbf3f6acaeea54029.png
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