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Updated on : 2022-09-05

Solution

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Correct option is A)

$x_{1}=21 wt_{2}$

and similarly the coordinate of the second event is

$x_{2}=21 w(t+τ)_{2}−l$

The distance between the two events is obviously,

$x_{1}−x_{2}=l−wτ(t+2τ )=0.242km$

in the reference frame fixed on the earth.

For the two events to occur at the same point in the reference frame $K$, moving with constant velocity $V$ relative to the earth, the distance travelled by the frame in the time interval $T$ must be equal to the above distance.

Thus $Vτ=l−wτ(t+2τ )$

So, $V=τ1 −wτ(t+2τ )=4.03m/s$

The frame $K$ must clearly be moving in a direction opposite to the train so that if (for example) the origin of the frame coincides with the point $x_{1}$ on the earth at time $t$, it coincides with the point $x_{2}$ at time $t+τ$.

Solve any question of Motion in a Straight Line with:-

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