A train starting from rest moves with a uniform acceleration of $0.2 m / s^{2}$ for 5 minutes. Calculate the speed acquired and the distance travelled in this time.

Question

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Answer 1

Initial velocity, $u = 0 m / s$
Final velocity, $y v = ?$
Acceleration, $a = 0.2 m / s^{2}$
Time, $t = 5 m i n = 5 \times 60 = 300 s e c$

Using first equation of motion to obtain the final speed:
$v = u + a t$
$v = 0 + 0.2 \times 300 = 60 m / s$

And the distance travelled is
$s = u t + \frac{1}{2} α t^{2}$

$s = 0 \times 300 + \frac{1}{2} \times 0.2 \times 300 \times 300$

$s = 0 + 9000 = 9000 m = 9 k m$

Answer 2

Initial velocity,

u = 0 m / s

Final velocity,

y v = ?

Acceleration,

a = 0.2 m / s^{2}

Time,

t = 5 m i n = 5 \times 60 = 300 s e c

Using first equation of motion to obtain the final speed:

v = u + a t

v = 0 + 0.2 \times 300 = 60 m / s

And the distance travelled is

s = u t + \frac{1}{2} α t^{2}

s = 0 \times 300 + \frac{1}{2} \times 0.2 \times 300 \times 300

s = 0 + 9000 = 9000 m = 9 k m