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Question

A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have been taken 1 hours less for the same journey. Find the speed of the train.

Solution
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Let the speed of the train =v

time=distancespeed

in a case 1

time(t)=360/v

in case 2
time(T)=360/v+5

As,
tT=1

So,

360v360v+5=1

360(v+5vv(v+5))=1

360(5)=v(v+5)

v2+5v1800=0

v2+45v40v1800=0

(v+45)(v40)=0

v=45,40

As speed cannot be negative,

Thus a speed of the train is 40km/hr2

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