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Given distance = 63 km.

Original speed of trian = x cm/hr.

time $=speeddistance =x63 $ hrs

And it travels a distance of 72 km at a avg speed of 6 km / hr more than original speed.

distance = 72 km

speed = (x+6) km / m.

time $=2+672 $ hrs.

If it takes 3 hrs to complete the whose journey $x63 +x+672 $ = 3 hrs

63(x+6)+72x = 3x(x+6)

21(x+6)+24x = x(x+6).

$45x+21×6=x_{2}+6x$

$x_{2}−39x−126=0$

(x-42) (x+3) = 0

$∴$ x = 42 [original avg speed]

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