A tree is brokenby wind- itsupper part touches the ground a point 10 meters from the foot of the tree and makes an angle of 45 with the ground- The entire length of the tree is 15 m20 m10 -1 - sqrt-2- m10 -1 - sqrt-3-2- m

Question

Toppr Admin · Accepted Answer

AC - 10 - ABBC - BC-apos- - -x221A-102-102-10-x221A-2AC - AB - BC - 10 -x221A-2-xA0- -1-

A tree is brokenby wind, itsupper part touches the ground at a point 10 meters from the foot of the tree and makes an angle of 45 with the ground. The entire length of the tree is
$15 m$
$20 m$
$10 (1 +$ $\sqrt{2}$ ) m
$10 (1 +$ $\sqrt{3 / 2}$ ) m

AC = 10 = AB
BC = BC' = $\sqrt{(10^{2} + 10^{2})} = 10 \sqrt{2}$
AC = AB + BC = 10 ( $\sqrt{2}$ +1)

A tree is brokenby wind, itsupper part touches the ground at a point 10 meters from the foot of the tree and makes an angle of 45 with the ground. The entire length of the tree is 15m20m10(1+ √2) m10(1+ √3/2) m

AC = 10 = ABBC = BC' = √(102+102)=10√2AC = AB + BC = 10 (√2 +1)

A tree is brokenby wind, itsupper part touches the ground at a point 10 meters from the foot of the tree and makes an angle of 45 with the ground. The entire length of the tree is
$15 m$
$20 m$
$10 (1 +$ $\sqrt{2}$ ) m
$10 (1 +$ $\sqrt{3 / 2}$ ) m

AC = 10 = AB
BC = BC' = $\sqrt{(10^{2} + 10^{2})} = 10 \sqrt{2}$
AC = AB + BC = 10 ( $\sqrt{2}$ +1)