0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A two-digit number has tens digit greater than the unit's digit. If the sum of its digits is equal to twice the difference, how many such numbers are possible?

Solution
Verified by Toppr

Let the two numbers be a,b

Given,
a>b

(a+b)=2(ab)

a=3b

Put values of b such that a<10 (otherwise it would be a 3 digit number)

b=1,2,3

a=3,6,9

So, the possible numbers are 31,62,93.

Hence, 3 such numbers are possible.

Was this answer helpful?
0
Similar Questions
Q1
A two-digit number has tens digit greater than the unit's digit. If the sum of its digits is equal to twice the difference, how many such numbers are possible?
View Solution
Q2
A 2-digit number has tens digit greater than the unit is digit if the sum of its digits is equal to twice the difference, no. of such numbers possible are
View Solution
Q3
Sum of the digits of a two digit number is 5 and difference of the digits is 1. Also, the tens place is greater than the unit place digit. The number is .
View Solution
Q4
The units digit of a two-digit number is greater than its tens digit by 2 and the product of that number by the sum of its digits is 144. Find the number.
View Solution
Q5

In a three digit number the hundreds digit is twice the tens digit while the units digit is thrice the tens digit also the sum of its digits is 18 find the number

View Solution