Question

A uniform electric field having strenght is existing in x-y plane as shown in figure. Find the p.d. between origin O & A (d,d,0),

119723_b46138f6c280477d978109375631aa2d.png

A
Ed(cosθ+sinθ)
B
Ed(sinθcosθ)
C
2Ed
D
None of these
Solution
Verified by Toppr

When the electric field E in x-y plane makes angle θ with the x-axis , the electric filed can be written as E=Ecosθ^i+Esinθ^j
Thus, Ex=Ecosθ , Ey=Esinθ and Ez=0
Since E=Vdr
So, dVx=Exdx, dVy=Eydy and dVz=Ezdz
Now ingratiating, Vx=0dEcosθdx=Ecosθ(0d)=Edcosθ
Vy=0dEsinθdy=Esinθ(0d)=Edsinθ
and Vz=0
Thus, potential between O and A is V=Vx+Vy+Vz=Edcosθ+Edsinθ

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