A uniform electric field of 10 NC-1- exists in the vertically downward direction- Find the increase in the electric potential as one goes up through a height of 50 cm-

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The electric field in the region is -E-10 N-c-The distance covered by the particle is - S-50cm-0-5m-The relation between the electric potential and the electric field is -E-dfrac-dV-dr-160-or- -V-E-times r-10-times 0-5-5- V-

A uniform electric field of $$10 NC^{-1}$$ exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of $$50$$ cm.

The electric field in the region is $$E=10 N/c$$
The distance covered by the particle is $$ S=50cm=0.5m$$

The relation between the electric potential and the electric field is :

$$E=\dfrac{dV}{dr}$$
or, $$V=E\times r$$

$$=10\times 0.5=5\ V$$.

A uniform electric field of $$10 NC^{-1}$$ exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of $$50$$ cm.

The electric field in the region is $$E=10 N/c$$The distance covered by the particle is $$ S=50cm=0.5m$$The relation between the electric potential and the electric field is :$$E=\dfrac{dV}{dr}$$ or, $$V=E\times r$$$$=10\times 0.5=5\ V$$.

The electric field in the region is $$E=10 N/c$$
The distance covered by the particle is $$ S=50cm=0.5m$$

The relation between the electric potential and the electric field is :

$$E=\dfrac{dV}{dr}$$
or, $$V=E\times r$$

$$=10\times 0.5=5\ V$$.