A uniform electric field pointing in positive x-direction exists in a region. Let A be the origin, B be the point on the x-axis at x = +1 cm and C be the point on the y-axis at y = +1 cm. Then the potentials at the points A, B and C satisfy:

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Toppr Admin · Accepted Answer

As E-x2212-dVdx so potential will less near the electric field direction-Thus- VA-VC-gt-VB-x21D2-VA-gt-VB-VC-gt-VB

A uniform electric field pointing in positive x-direction exists in a region. Let A be the origin, B be a point on the x-axis at x =+1cm and C be the point on the y-axis at y =+1cm. Then, the potential at points A, B and C satisfy :VA<VBVA>VBVA<VCVA>VC

As E=−dVdx so potential will less near the electric field direction.Thus, VA=VC>VB⇒VA>VB,VC>VB

As $E = - \frac{d V}{d x}$ so potential will less near the electric field direction.
Thus, $V_{A} = V_{C} > V_{B} \Rightarrow V_{A} > V_{B}, V_{C} > V_{B}$