A uniform rod AB of mass m and length ell is in equilibrium with the of two identical inextensible strings as shown in the figure- Choose the correct option -s-After cutting the string -2- motion of centre of mass of the rod is circularAfter cutting the string -2- motion of centre of mass of the rod is not circularJust after cutting the string -2- the acceleration of point A along the string -1- is zero-Just after cutting the string -2- the acceleration of point A perpendicular to the string -1- is not zero-

Question

Toppr Admin · Accepted Answer

The correct options are
B After cutting the string (2) motion of centre of mass of the rod is not circular
C Just after cutting the string (2) the acceleration of point A along the string (1) is zero.
D Just after cutting the string (2) the acceleration of point A perpendicular to the string (1) is not zero.
The point $A$ will move in a circular motion after cutting the string $2$ . But, relative to the point $A$ , the center of mass will also move in a circular motion, keeping $A$ its center. Therefore in the ground frame, the motion of the center of mass will not be circular.
The instantaneous velocity of the point $A$ will be 0 after cutting the string $2$ . And it will vary with the acceleration $a = \frac{{v^{2}}_{instant}}{r}$ . Therefore, its acceleration along the string will be $0$ .
The acceleration of the point $A$ perpendicular to the string $1$ is not zero because of the unbalanced forces along the direction.