Question

A uniform rod of length L is placed symmetrically on two walls as shown in the figure. The rod is in equilibrium. If $N_1$ and $N_2$ are the normal forces exerted by the walls on the rod then

• A. $N_1$ = $N_2$
• B. $N_1$ < $N_2$
• C. $N_1$ and $N_2$ would be in the vertical directions
• D. $N_1$ > $N_2$

Answer 1

Answer: (A)

$N_1\times \frac{l}{4}=N_2\times \frac{l}{4}$

$N_1=N_2$

(by torque conservation)

Correct option is (C).