A uniformly charged disc has a pin hole at its centre. The electric field at the centre of the disc is zero

Question

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Answer 1

The electric field due to disc is superposition of electric field due to its constituent ring as given in statement-2.
Statement 1 is true, statement-2 is true, statement-2 is a correct explanation of statement-1.

Answer 2

The electric field due to disc is superposition of electric field due to its constituent ring as given in statement-2.
Statement 1 is true, statement-2 is true, statement-2 is a correct explanation of statement-1.

A uniformly charged disc has a pin hole at its centre. The electric field at the centre of the disc is zero

Disc can be supported to be made up of many rings. also electric field at the centre of uniformly charged ring is zero

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

Assertion is correct but Reason is incorrect

Assertion is incorrect but Reason is correct

The electric field due to disc is superposition of electric field due to its constituent ring as given in statement-2.
Statement 1 is true, statement-2 is true, statement-2 is a correct explanation of statement-1.

The electric field at O is :

A charge $q$ is uniformly distributed over thin half ring of radius R. The electric field at the centre of the ring is :

A flat circular disc has a charge +Q uniformly distributed on the disc. A charge +q is thrown with kinetic energy E towards the disc along its normal axis. The charge q will :

A spherical shell has uniform charge density $8.8 \times 1 0^{- 11} C / m^{2}$ . If a pin hole is made in the surface of the shell then electric field in the hole in N/C is :
$ϵ_{0} = 8.8 \times 1 0^{- 12}$ S.I units

An annular disc has inner and outer radius R $_{1}$ and R $_{2}$ respectively. Charge is uniformly distributed. Surface charge density is $σ$ . Find the electric field at any point distant y along the axis of the disc.

A uniformly charged disc has a pin hole at its centre. The electric field at the centre of the disc is zero

Disc can be supported to be made up of many rings. also electric field at the centre of uniformly charged ring is zero

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

Assertion is correct but Reason is incorrect

Assertion is incorrect but Reason is correct

The electric field due to disc is superposition of electric field due to its constituent ring as given in statement-2.Statement 1 is true, statement-2 is true, statement-2 is a correct explanation of statement-1.

The electric field at O is :

A charge q is uniformly distributed over thin half ring of radius R. The electric field at the centre of the ring is :

A flat circular disc has a charge +Q uniformly distributed on the disc. A charge +q is thrown with kinetic energy E towards the disc along its normal axis. The charge q will :

A spherical shell has uniform charge density 8.8×10−11C/m2. If a pin hole is made in the surface of the shell then electric field in the hole in N/C is : ϵ0​=8.8×10−12 S.I units

An annular disc has inner and outer radius R1​ and R2​ respectively. Charge is uniformly distributed. Surface charge density is σ. Find the electric field at any point distant y along the axis of the disc.

The electric field due to disc is superposition of electric field due to its constituent ring as given in statement-2.
Statement 1 is true, statement-2 is true, statement-2 is a correct explanation of statement-1.

A charge $q$ is uniformly distributed over thin half ring of radius R. The electric field at the centre of the ring is :

A spherical shell has uniform charge density $8.8 \times 1 0^{- 11} C / m^{2}$ . If a pin hole is made in the surface of the shell then electric field in the hole in N/C is :
$ϵ_{0} = 8.8 \times 1 0^{- 12}$ S.I units

An annular disc has inner and outer radius R $_{1}$ and R $_{2}$ respectively. Charge is uniformly distributed. Surface charge density is $σ$ . Find the electric field at any point distant y along the axis of the disc.