A vehicle of mass 100 kg is moving with a velocity of 5 m-s- To stop it in dfrac -1-10-s the required force in opposite direction is-5000 N500 N50 N1000 N

Question

Toppr Admin · Accepted Answer

F-x394-P-x394-t-m-V2-x2212-V1-x394-t-100-0-x2212-5-xD7-101-x2212-5000N

A vehicle of mass $100 k g$ is moving with a velocity of $5 m / s$ . To stop it in $\frac{1}{10} s$ the required force in opposite direction is:
$5000 N$
$500 N$
$50 N$
$1000 N$

$F = \frac{Δ P}{Δ t} = \frac{m (V_{2} - V_{1})}{Δ t} = \frac{100 (0 - 5) \times 10}{1} = - 5000 N$

A vehicle of mass 100kg is moving with a velocity of 5m/s. To stop it in 110s the required force in opposite direction is:5000N500N50N1000N

F=ΔPΔt=m(V2−V1)Δt=100(0−5)×101=−5000N

A vehicle of mass $100 k g$ is moving with a velocity of $5 m / s$ . To stop it in $\frac{1}{10} s$ the required force in opposite direction is:
$5000 N$
$500 N$
$50 N$
$1000 N$

$F = \frac{Δ P}{Δ t} = \frac{m (V_{2} - V_{1})}{Δ t} = \frac{100 (0 - 5) \times 10}{1} = - 5000 N$