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Question

A verandah of width $$2.25$$ m is constructed all along outside a room which is $$5.5$$ m long and $$4$$ m wide. Find the cost of cementing the floor of the verandah at the rate of Rs. $$200$$ per $$m^2$$.

Solution
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A verandah of width $$2.25$$m is constructed all along outside a room which is $$5.5$$m long and $$4$$m wide.

The length of room$$=5.5$$ m and width of the room$$=4$$ m

The length of the room with verandah$$=5.5+2.25+2.25=10$$ m

The width of the room with verandah$$=4+2.25+2.25=8.5$$ m

Area of verandah$$=$$Area of the room with verandah$$-$$Area of the room without a verandah

$$=$$ Area of ABCD$$-$$Area of EFGH

$$=(AB\times AD)-(EF\times EH)$$

$$=(10\times 8.5)-(5.5\times 4)\\$$
$$=85-22\\$$
$$=63m^2$$

The cost of cementing $$1m^2$$ the floor of verandah $$=$$Rs. $$200$$

The cost of cementing $$63 m^2$$ the floor of verandah$$=200\times 63=$$Rs. $$12,600$$.

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