A vertical straight conductor carries a current vertically upwards. A point $P$ lies to the east of it at a small distance and another point $Q$ lies to the west at the same distance the magnetic field at $P$ is :

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Answer 1

As per Biot Savart Law, Magnetic field at a point is inversely proportional to square of distance from the current carrying conductor. Therefore magnitude of magnetic field is same at both points P and Q, irrespective of their position from the conductor.

Answer 2

As per Biot Savart Law, Magnetic field at a point is inversely proportional to square of distance from the current carrying conductor. Therefore magnitude of magnetic field is same at both points P and Q, irrespective of their position from the conductor.

A vertical straight conductor carries a current vertically upwards. A point $P$ lies to the east of it at a small distance and another point $Q$ lies to the west at the same distance the magnetic field at $P$ is :

greater than at $Q$

same as at $Q$

less than at $Q$

greater or less than at $Q$ depending upon the strength of current

As per Biot Savart Law, Magnetic field at a point is inversely proportional to square of distance from the current carrying conductor. Therefore magnitude of magnetic field is same at both points P and Q, irrespective of their position from the conductor.

A straight conductor carries a current along the z-axis. Consider the points A(a, 0, 0), B(0, -a, 0), C(-a, 0, 0) and D(0, a, 0) :

P & Q are two points at the same distance and in the same horizontal plane form a current carrying vertical conductor. The point P is located towards the west and the point Q is towards the east. The current is vertically downwards. If $B_{P}$ & $B_{Q}$ be the net magnetic fields at P & Q then :

Magnetic lines of force due to a long straight conductor carrying current are

.A rectangular loop carrying current I is located near an infinite long straight conductor carrying current I as shown in the figure. The loop,

A straight vertical conductor carries a current. At a point $5 c m$ due north of it, the magnetic induction is found to be $20 T$ due east. The magnitude of magnetic induction at a point $10 c m$ east of it will be_____

Revise with Concepts

Magnetic Field Due to Current Carrying Element - Biot - Savart Law

A vertical straight conductor carries a current vertically upwards. A point P lies to the east of it at a small distance and another point Q lies to the west at the same distance the magnetic field at P is :

greater than at Q

same as at Q

less than at Q

greater or less than at Q depending upon the strength of current

As per Biot Savart Law, Magnetic field at a point is inversely proportional to square of distance from the current carrying conductor. Therefore magnitude of magnetic field is same at both points P and Q, irrespective of their position from the conductor.

A straight conductor carries a current along the z-axis. Consider the points A(a, 0, 0), B(0, -a, 0), C(-a, 0, 0) and D(0, a, 0) :

P & Q are two points at the same distance and in the same horizontal plane form a current carrying vertical conductor. The point P is located towards the west and the point Q is towards the east. The current is vertically downwards. If BP​ & BQ​ be the net magnetic fields at P & Q then :

Magnetic lines of force due to a long straight conductor carrying current are

.A rectangular loop carrying current I is located near an infinite long straight conductor carrying current I as shown in the figure. The loop,

A straight vertical conductor carries a current. At a point 5 cm due north of it, the magnetic induction is found to be 20 T due east. The magnitude of magnetic induction at a point 10 cm east of it will be_____

Revise with Concepts

Magnetic Field Due to Current Carrying Element - Biot - Savart Law

A vertical straight conductor carries a current vertically upwards. A point $P$ lies to the east of it at a small distance and another point $Q$ lies to the west at the same distance the magnetic field at $P$ is :

greater than at $Q$

same as at $Q$

less than at $Q$

greater or less than at $Q$ depending upon the strength of current

P & Q are two points at the same distance and in the same horizontal plane form a current carrying vertical conductor. The point P is located towards the west and the point Q is towards the east. The current is vertically downwards. If $B_{P}$ & $B_{Q}$ be the net magnetic fields at P & Q then :

A straight vertical conductor carries a current. At a point $5 c m$ due north of it, the magnetic induction is found to be $20 T$ due east. The magnitude of magnetic induction at a point $10 c m$ east of it will be_____