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A vessel was found to contain equal masses of $$CO(g), CO_{2}(g), H_{2}O(g),H(g)$$ at $$t=t_{0}$$. At $$t=3t_{0}\ mol$$ ratio of $$CO_{2}$$ and $$H_{2}O$$ was found to be $$CO_{2}$$ and $$H_{2}O$$ was found to be $$\dfrac{9}{22}$$. Which one of the following is correct

$$Kc$$ for $$CO(g)+H_{2}O(g)\rightleftharpoons CO_{2}(g)+H_{2}(g)$$ is $$\dfrac{63}{13}$$

$$mole\ ratio\ of\ H_{2}\ and\ CO\ at\ t=2t_{0}\ is\ 14:1$$

$$mol\ fraction\ of\ H_{2}\ at\ t=2t_{0}=\dfrac{1}{4}$$

$$K_{C}\ for\ CO(g)+H_{2}O(g)\rightleftharpoons CO_{2}(g)+H_{2}(g)$$ is $$1$$

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Solution

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Correct option is A. $$Kc$$ for $$CO(g)+H_{2}O(g)\rightleftharpoons CO_{2}(g)+H_{2}(g)$$ is $$\dfrac{63}{13}$$

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