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A water tap fills a tank in p hours and the tap of the bottom of the tank empties it in q hours. If p is less than q and when both the taps are open, the tank is filled in r hours. Then

A
$$\displaystyle\frac{1}{r}=\frac{1}{p}+\frac{1}{q}$$
B
$$\displaystyle\frac{1}{r}=\frac{1}{p}-\frac{1}{q}$$
C
$$r=p+q$$
D
$$r=p-q$$
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Solution
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Correct option is B. $$\displaystyle\frac{1}{r}=\frac{1}{p}-\frac{1}{q}$$

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