A wave in a string has an amplitude of 2 cm- The wave travels in the -ve direction of x-axis with a speed of 128ms-1- and it is noted that 5 complete waves fit in 4m length of the string- The equation describing the wave is y-0-02-m sin-7-85x-100 5t-y-0-02-m sin-15-7x-2010 5t-y-0-02-m sin-15-7x-2010 5t-y-0-02-m sin-7-85x-100 5t-

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Toppr Admin · Accepted Answer

Amplitude -2cm-0-02mv-128m-s5-x3BB-4-x27F9-x3BB-45-0-8m-x3BD-1280-8-160Hz-x3C9-2-x3C0-x3BD-2-x3C0-xD7-160-1005k-2-x3C0-x3BB-2-x3C0-0-8-7-85Therefore-y-0-02sin-7-85x-x2212-1005t-

Amplitude =2cm=0.02mv=128m/s5λ=4⟹λ=45=0.8mν=1280.8=160Hzω=2πν=2π×160=1005k=2πλ=2π0.8=7.85Therefore,y=0.02sin(7.85x−1005t)

Amplitude $= 2 c m = 0.02 m$

$v = 128 m / s$

$5 λ = 4 ⟹ λ = \frac{4}{5} = 0.8 m$

$ν = \frac{128}{0.8} = 160 H z$

$ω = 2 π ν = 2 π \times 160 = 1005$

$k = \frac{2 π}{λ} = \frac{2 π}{0.8} = 7.85$

Therefore,

$y = 0.02 s i n (7.85 x - 1005 t)$