A wheel of radius R is to rotate about its natural axis and I is its moment of inertia- If a tangential force F is applied on the wheel along its rim- then angular acceleration of wheel is-IFRdfrac-FR-I-dfrac-IF-R-dfrac-IR-F-

Question

Toppr Admin · Accepted Answer

The torque is given using the relation -x2192-x3C4-x2192-F-xD7-x2192-Ror-x3C4-I-x3B1-or-x3B1-FRI

A wheel of radius $R$ is free to rotate about its natural axis and $I$ is its moment of inertia. If a tangential force $F$ is applied on the wheel along its rim, then angular acceleration of wheel is:
$I F R$
$\frac{F R}{I}$
$\frac{I F}{R}$
$\frac{I R}{F}$

The torque is given using the relation
$\to τ = \to F \times \to R$
or
$τ = I α$
or
$α = \frac{F R}{I}$

A wheel of radius R is free to rotate about its natural axis and I is its moment of inertia. If a tangential force F is applied on the wheel along its rim, then angular acceleration of wheel is:IFRFRIIFRIRF

The torque is given using the relation →τ=→F×→Rorτ=Iαorα=FRI

A wheel of radius $R$ is free to rotate about its natural axis and $I$ is its moment of inertia. If a tangential force $F$ is applied on the wheel along its rim, then angular acceleration of wheel is:
$I F R$
$\frac{F R}{I}$
$\frac{I F}{R}$
$\frac{I R}{F}$

The torque is given using the relation
$\to τ = \to F \times \to R$
or
$τ = I α$
or
$α = \frac{F R}{I}$